Completed proof of reflection

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\subsubsection{Proof of H1}
\todo{Relire + réeexpliquer pourquoi ça prouve}
\label{sec:coproductConstr}
We will define the sums of the form $X \oplus_i L_0^i Y$ in $\BB_i$.
\[
X \oplus_i L_0^i Y := \left(R_{i-1}^i \oplus_{i-1} L_0^{i-1} Y, (R_0^{i-1} \inj_1^{i-1})_\UU \circ \Cstr_i^X \circ (\inj_1^{i-1} \circ \dash)^{-1}\right)
X \oplus_i L_0^i Y := \left(R_{i-1}^i X \oplus_{i-1} L_0^{i-1} Y, (R_0^{i-1} \inj_1^{i-1})_\UU \circ \Cstr_i^X \circ (H_iF_{i-1}\inj_1^{i-1})^{-1}\right)
\]
Here, $(\inj_1^{i-1} \circ \dash)^{-1}$ is the inverse of the isomorphism of hypothesis H3', and
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The second injector is defined as follows:
\[
inj_2^i := (\varepsilon_i \oplus_i \id_{L_0^i Y}) \circ L_{i-1}^i \inj_2^{i-1}
\inj_2^i := (\varepsilon_i \oplus_i \id_{L_0^i Y}) \circ L_{i-1}^i \inj_2^{i-1}
\]
Where $\varepsilon_i$ is the counit of the adjunction $R_{i-1}^i \vdash L_{i-1}^i$, going from $L_{i-1}^i R_{i-1}^i X$ to $X$.
This goes from $L_0^i Y = L_{i-1}^i L_0^{i-1} Y$ to $L_{i-1}^i(R_{i-1}^i X \oplus_{i-1} L_0^{i-1} Y)$, which is equivalent to $L_{i-1}^i R_{i-1}^i X \oplus_i L_0^i Y)$ as $L_{i-1}^i$ is a left-adjoint functor and therefore it preserves colimits; then goes to $X \oplus_i L_0^i Y$.
This goes from $L_0^i Y = L_{i-1}^i L_0^{i-1} Y$ to $L_{i-1}^i(R_{i-1}^i X \oplus_{i-1} L_0^{i-1} Y)$, which is equivalent to $L_{i-1}^i R_{i-1}^i X \oplus_i L_0^i Y$ as $L_{i-1}^i$ is a left-adjoint functor and therefore it preserves colimits; then goes to $X \oplus_i L_0^i Y$.
We will now show that this definition is actually a definition of the coproduct in $\BB_i$.
To that extent, we take two objects $X$ and $Z$ in $\BB_i$, $Y$ in $\TSet$ and two morphisms of $\BB_i$ $\varphi_1 : X \to Z$ and $\varphi_2 : L_0^i Y \to Z$.
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\subsubsection{Proof of H3}
We need to prove that, for any objects $(X,\Cstr)$ in $\BB_i$ and $Y$ in $\TSet$, that the morphism
$F_i(\inj_1^i) : F_i(X,\Cstr) \to F_i((X,\Cstr) \oplus L_0^i Y)$ is an isomorphism.
We know from \autoref{sec:coproductConstr} that $\inj_1^i := \inj_1^{i-1}$ as a morphism of $\BB_{i}$ is a morphism $\BB_{i-1}$ that verifies some equalities.
We also know from the last induction step that $F_{i-1}\inj_1^{i-1}$ is an isomorphism.
\[
(X,\Cstr) \oplus L_0^iY \simeq (X \oplus L_0^{i-1}Y, (R_0^{i-1}\inj_1^{i-1})_\UU \circ \Cstr \circ (H_iF_{i-1}\inj_1^{i-1})^{-1})
\]
\section{Misc}
@ -779,15 +789,14 @@
\section{$F_i \vdash G_i$ reflection}
\label{apx:FG-refl}
\todo{La preuve :/}
We want to find, for each object $(X,(B,g))$ of $\CC_i = (X : \CC_{i-1}) \times (\Set/H_i(X))$, an isomorphism $(X,(B,g)) \to F_iG_i(X,(B,g))$. $g$ is a morphism from $B$ to $H_i(X)$
\[\begin{array}{rcl}
F_iG_i(X,\Rtsc)
&=& F_iW_i(G_{i-1}X,\Rtsc)\\
&=& F_i(G_{i-1}X \oplus L_0^{i-1}H_\bullet(G_{i-1}X,\Rtsc),\widetilde{\inj_2})\\
&=&(F_{i-1} \times \id)\left(G_{i-1}X \oplus L_0^{i-1}\Hbar_\bullet(G_{i-1}X,\Rtsc),(A,h)\right)\\
&=&\left(F_{i-1}(G_{i-1}X \oplus L_0^{i-1}\Hbar_\bullet(G_{i-1}X,\Rtsc)),(A,h)\right)
F_iG_i(X,(B,g))
&=& F_iW_i(G_{i-1}X,(B,g))\\
&=& F_i(G_{i-1}X \oplus L_0^{i-1}H_\bullet(G_{i-1}X,(B,g)),\widetilde{\inj_2})\\
&=&(F_{i-1} \times \id)\left(G_{i-1}X \oplus L_0^{i-1}\Hbar_\bullet(G_{i-1}X,(B,g)),(A,h)\right)\\
&=&\left(F_{i-1}(G_{i-1}X \oplus L_0^{i-1}\Hbar_\bullet(G_{i-1}X,(B,g))),(A,h)\right)
\end{array}\]
Where $(A,h)$ is the pullback defined as
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% END OF GENERATED LATEX
\end{center}
We can extend this pullback using the two isomorphisms given by the induction hypothesis and hypothesis H3.
We can extend this pullback using the two isomorphisms given by the induction hypothesis and hypothesis H3. This pullback is over the injection morphism $\inj_2$ of the coproduct, so the new pullback object is the second component of the $\bullet \oplus B$ i.e. $B$.
\begin{center}
% YADE DIAGRAM E2.json
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% END OF GENERATED LATEX
\end{center}
The first component of the isomorphism is the following isomorphism, where $\eta_{i-1}^{FG}$ if the counit of the adjunction $F_{i-1} \vdash G_{i-1}$, that we know to be an isomorphism from the induction hypothesis.
\begin{center}
% YADE DIAGRAM E3.json
% GENERATED LATEX
\input{graphs/E3.tex}
% END OF GENERATED LATEX
\end{center}
And the second component is made using the isomorphism constructed by the pullback, that makes the diagram commute.
\begin{center}
% YADE DIAGRAM E4.json
% GENERATED LATEX
\input{graphs/E4.tex}
% END OF GENERATED LATEX
\end{center}
\end{document}
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